((2^2x)/2^7)-(9*2^(2x-1))+256=0

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Solution for ((2^2x)/2^7)-(9*2^(2x-1))+256=0 equation: 



((2^2x)/2^7)-(9*2^(2x-1))+256=0

We get rid of parentheses

2^2x/2^7-(9*2^(2x-1))+256=0

We multiply all the terms by the denominator


2^2x-((9*2^(2x-1)))*2^7+256*2^7=0

We add all the numbers together, and all the variables

2^2x-((9*2^(2x-1)))*2^7+32768=0

We move all terms containing x to the left, all other terms to the right

2^2x-((9*2^(2x-1)))*2^7=-32768

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